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10a^2+7a-0.8=0
a = 10; b = 7; c = -0.8;
Δ = b2-4ac
Δ = 72-4·10·(-0.8)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-9}{2*10}=\frac{-16}{20} =-4/5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+9}{2*10}=\frac{2}{20} =1/10 $
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